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  • Stuck here, help me understand: HgCl2 and I2 both when dissolved in water containing I- ions the pair of species formed is :

HgCl2 and I2 both when dissolved in water containing I- ions the pair of species formed is :

  • Option 1)

    \text{HgI}_2 ,\text{I}_3^ -

  • Option 2)

    \text{HgI}_2 ,\text{I}^ -

  • Option 3)

    \text{HgI}_4^{2 - } ,\text{I}_\text{3}^ -

  • Option 4)

    \text{Hg}_\text{2} \text{I}_\text{2} ,\text{I}^ -

 

Answers (2)

best_answer

As we discussed in the concept ID

Ammonia and its salt with nessler's reagent -

Gives brown precipitate due to the formation of Millon's base

- wherein

  1. K_{2}HgI_{4}\rightleftharpoons 2KI+HgI_{2}
  2. HgI_{2}+2NH_{3}\rightarrow I-Hg-NH_{2}+NH_{4}I
  3. 2NH_{2}-Hg-I+H_{2}O\rightarrow NH_{2}-Hg-O-Hg-I+NH_{4}I
  4. 2K_{2}HgI_{4}+NH_{3}+3KOH\rightarrow H_{2}N-Hg-O-Hg-I+7KI+2H_{2}O

 

 H_{g}Cl_{2}+4I^{-}\rightarrow \left [ H_{g}I_{4} \right ]^{2-}+2Cl^{-}

I_{2}+I^{-}\rightarrow I_{3}^{-}


Option 1)

\text{HgI}_2 ,\text{I}_3^ -

Incorrect option

Option 2)

\text{HgI}_2 ,\text{I}^ -

Incorrect option

Option 3)

\text{HgI}_4^{2 - } ,\text{I}_\text{3}^ -

Correct option

Option 4)

\text{Hg}_\text{2} \text{I}_\text{2} ,\text{I}^ -

Incorrect option

Posted by

prateek

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hgi42- and i3-

Posted by

jhanu joy

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