Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Taking the Bohr radius as the radius of <img alt="\mathrm{Li^

Taking the Bohr radius as \mathrm{a_0= 53\: pm, } the radius of \mathrm{Li^{++} } ion in its ground state, on the basis of Bohr’s model, will be about
 

Option: 1

\mathrm{53 \: pm}
 


Option: 2

\mathrm{27\: pm}


Option: 3

\mathrm{18\: pm}


Option: 4

\mathrm{13\: pm}


Answers (1)

best_answer

On the basis of Bohr's model, \mathrm{r=\frac{n^2 h^2}{4 \pi^2 m K Z e^2}=a_0 \frac{n^2}{Z} \: }

\mathrm{For \: \: \mathrm{Li}^{++}ion, Z=3, n=1 } for ground state.

Given,\mathrm{ a_0=53 \mathrm{pm}}

\mathrm{ \therefore \quad r=\frac{53 \times 1^2}{3}=18 \mathrm{pm} }

Hence option 3 is correct.
 

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 irregularities under investigation; NTA says full cooperation being extended to agencies
anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided
anam-khan

NEET 2026: Odisha aspirant dies by suicide fearing failure

Latest Question