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  • The activation energy of the reaction can be determined if we plot.Option: 1 k vs T, the slope of the line will se equal to <img alt="\mathrm{E_{a}}"

The activation energy of the reaction can be determined if we plot.

Option: 1

k vs T, the slope of the line will se equal to \mathrm{E_{a}}


Option: 2

\mathrm{lnk\: vs\: \frac{1}{T}}, The slope of the line will be equal to \mathrm{-E_{a}/R}


Option: 3

\mathrm{\frac{1}{[A]_{t} }vs\: t}, The slope of the line will be equal to \mathrm{E_{a}}


Option: 4

plot \mathrm{ln[A]_{t}\: vs\: t}, The slope of the line will be equal to \mathrm{-E_{a}/R}


Answers (1)

best_answer

\mathrm{k =A e^{-E_{a} / R T} }
\mathrm{\ln k =\ln A-\frac{E_{a}}{R}\left(\frac{1}{T}\right) \quad }
\mathrm{y =k+m x}
\mathrm{\text { slope }=m =-E_{a} / R }.

Posted by

Divya Prakash Singh

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