Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The area of plates of a parallel plate capacitor is A the distance between the plates is <img alt="1100 \mathrm{~mm}" src="https://entrancecorner.oncodecogs.com/gif.latex?1100%20%5Cmathrm%7B%7Emm%7

The area of plates of a parallel plate capacitor is A the distance between the plates is 1100 \mathrm{~mm}. There are two dielectric sheet in it, one of dielectric constant 10 and thickness 6 \mathrm{~mm} and and the other of dielectric constant 5 and thickness 4 \mathrm{~mm}. The capacity of capacitor is.

Option: 1

1500 \leftarrow A


Option: 2

\frac{5000}{7} \leftarrow A


Option: 3

\frac{17}{35} \in \circ A


Option: 4

\frac{2}{5} \epsilon_0 A


Answers (1)

best_answer

 Capacity of parallel plate condenser = \mathrm{\frac{\epsilon_0 A}{d} }

with compound dielectric, c= \mathrm{\frac{\epsilon_0 A}{\left(\frac{d_1}{k_1}+\frac{d_2}{k_2}\right)} }

\mathrm{\begin{aligned} d_1 & =6 \mathrm{~mm}=6 \times 10^{-3} \mathrm{~m}, k_1=10 \\ d_2 & =4 \mathrm{~mm}=4 \times 10^{-3} \mathrm{~m}, k_2=5 \\ \therefore \quad c & =\frac{\epsilon_0 \mathrm{~A}}{\left(\frac{6 \times 10^{-3}}{10}+\frac{4 \times 10^{-3}}{5}\right)} \\ \text { or } c & =\frac{\epsilon_0 \mathrm{~A} \times 10^3}{\left(\frac{3}{5}+\frac{4}{5}\right)}=\frac{5 \times 1000}{7} \mathrm{\epsilon_0A} \\ c & =\frac{5000}{7} \mathrm{\epsilon_0A} \text { Ans. } \end{aligned} }
 

Posted by

chirag

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'PM Modi personally supervising the situation': Centre tells SC in NEET case
anam-khan

NEET Paper Leak Row: NTA informs SC of security overhaul, institutional reforms
anam-khan

Re-NEET 2026 City Intimation Slip LIVE: NTA MBBS admit card soon; direct link, login details, exam date

Latest Question