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  • The Capacitor shown in the Fig. is initially charged to a voltage V and the circuit is then closed. The charge on C is found to oscillate with frequency <img alt="\omega" src="/latex-image/?%5Comeg

The Capacitor shown in the Fig. is initially charged to a voltage V and the circuit is then closed. The charge on C is found to oscillate with frequency \omega. The frequency will be doubled if

Option: 1

the voltage V is doubled


Option: 2

both L and C are halved


Option: 3

both L and C are doubled


Option: 4

both L and C are creased by a factor \sqrt{2}


Answers (1)

best_answer

\mathrm{\omega=\sqrt{\frac{1}{L / 2 . C / 2}}=\sqrt{\frac{4}{L C}}=2\left(\sqrt{\frac{1}{L C}}\right)=2 \omega .}

Posted by

Rakesh

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