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Get Answers to all your Questions
The change in internal energy when a gas is cooled from 927bdegreeto 27 degree, is
A. 300% B. 200% C. 250% D. 75%
Answers (1)
@Aastha
T1 = 927 + 273 = 1200 K
T2 = 27 + 273 = 300 K
internal energy ∝ Temperature
U ∝ T
(U1 / U2) = (T1 / T2)
∴ [(U1 – U2) / U2] = [(T1 – T2) / T2]
∴ % change in energy = [{(1200 – 300) / (300)} × (100)]
= 3 × 100 = 300%
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