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The current \mathrm{I} through \mathrm{10\Omega} resistor in the circuit given below is

Option: 1

\mathrm{50\: mA}


Option: 2

\mathrm{20\: mA}


Option: 3

\mathrm{40\: mA}


Option: 4

\mathrm{80\: mA}


Answers (1)

best_answer

Here, diode \mathrm{D_2} is reverse biased while \mathrm{D_1} is forward biased. So, no current flows across \mathrm{D_2}, current flows through diode \mathrm{D_1}

\mathrm{ I=\frac{V}{R}=\frac{2}{10+15}=\frac{2}{15}=0.08 \mathrm{~A}=80 \mathrm{~mA} . }

Hence option 4 is correct.
 

Posted by

manish

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