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  • The current through  resistor in the given part of an electrical circuit, will be<

The current through 10\; \Omega resistor in the given part of an electrical circuit, will be

Option: 1

\frac{43}{55}A


Option: 2

\frac{566}{77}A


Option: 3

\frac{82}{77}A

 


Option: 4

\text {None of these}


Answers (1)

best_answer

Answer (3)

Let potential of junction is V

\frac{V-18}{10}+\frac{V-2}{8}+\frac{V-8}{4}+\frac{V-4}{6}=0

\frac{V}{10}+\frac{V}{8}+\frac{V}{4}+\frac{V}{6}=\frac{18}{10}+\frac{2}{8}+\frac{8}{4}+\frac{4}{6}

\left ( 12+15+30+20 \right )V

=\left ( 18 \times 12+2 \times 15+240+80 \right )

77V=566

V=\frac{566}{77}

Hence current in 10\; \Omega ,/=\frac{18-\frac{566}{77}}{10}=\frac{82}{77}A

Posted by

avinash.dongre

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