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  • The decomposition of follows:                n

The decomposition of \mathrm{A_3} follows:

                \mathrm{A_3 \stackrel{k_1}{\underset{k_{-1}}{\rightleftharpoons}} A_2+A-(1)}

               \mathrm{A_3+A \stackrel{K_2}{\longrightarrow} 2 A_2-(2)}

If  \mathrm{k_{-1}\left[A_2\right] < < < k_2\left[A_3\right]}, then the order of \mathrm{R x^n} w.r.t.
\mathrm{A_3 \, \, is =}  ?
 

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

Complex


Answers (1)

best_answer

In (2), \mathrm{\frac{d\left[A_2\right]}{d t}=k_2\left[A_3\right][A]}

\mathrm{ \text { By (1). } k_{e q}=\frac{k_1}{k_1}=\frac{\left[A_2\right][A]}{\left[A_3\right]} \Rightarrow[A]=\frac{k_1\left[A_3\right]}{k_{-1}\left[A_2\right]} }
        \mathrm{ \therefore \frac{d\left[A_2\right]}{d t}=\frac{k_1 k_2}{k_{-1}} \frac{\left[A_3\right]^2}{\left[A_2\right]} }

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