Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The electric field of a plane electromagnetic wave varies with time of amplitude <img alt="2 \mathrm{vm}^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?2%20%5Cmathrm%7Bvm%7D%5E%7B-1%7D"

The electric field of a plane electromagnetic wave varies with time of amplitude 2 \mathrm{vm}^{-1} propagating along z-axis. The average energy density of the magnetic field (\text{in}\; \mathrm{Jm}^{-3} ) is

Option: 1

13.29 \times 10^{-12}


Option: 2

8.86 \times 10^{-12}


Option: 3

17.72 \times 10^{-12}


Option: 4

4.43 \times 10^{-12}


Answers (1)

best_answer

Amplitude of electric field and magnetic field are related by
the relation.

\mathrm{\frac{\mathrm{E}_0}{\mathrm{~B}_0}=\mathrm{c}}

Average energy density of the magnetic field is \mathrm{\mathrm{uB}=\frac{1}{4} \frac{\mathrm{B}_{\mathrm{U}}^L}{\mu_0}=\frac{1}{4} \frac{\mathrm{E}_0^L}{\mu_0 \mathrm{c}^2}}

\begin{aligned} & \left(\because \mathrm{B}_0=\frac{\mathrm{E}_0}{\mathrm{c}}\right) \\ \\& =\frac{1}{4} \varepsilon_0 \mathrm{E}_0^2=\frac{1}{4} \times 8.854 \times 10^{-12} \times(2)^2=8.854 \times 10^{-12} \mathrm{~J} \mathrm{~m}^{-3}=8.86 \times 10^{-12} \mathrm{~J} \mathrm{~m}^{-3} \end{aligned}

Posted by

Pankaj Sanodiya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 Paper Leak: Biology lecturer, part of NTA's paper-setting committee for NEET, arrested
anam-khan

NEET Paper Leak: Student dies by suicide in Rajasthan’s Sikar amid controversy
anam-khan

NTA opens NEET UG 2026 re-exam correction window to modify address, select choice of cities

Latest Question