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  • The electric potential at the surface of an atomic nucleus of radius <img alt="9.0 \times 10^{-13} \mathrm{~c

The electric potential at the surface of an atomic nucleus (z=50) of radius 9.0 \times 10^{-13} \mathrm{~cm} is

Option: 1

9\times 10^{5}\ volt


Option: 2

8 \times 10^{6}\ volt


Option: 3

80\ volt


Option: 4

9\ volt


Answers (1)

best_answer

\begin{aligned} z \rightarrow \text { no. of protons } & =50 \\ \text { charge on } 1 \text { proton } & =+e \\ & =+1.6 \times 10^{-19 . C} \end{aligned} \\ charge, \\ \begin{aligned} q & =z e \\ & =50 \times 1.6 \times 10^{-19 c} \\ & =80 \times 10^{-19 c} \end{aligned}   
Now, \\ \text { electric potential, }\\ \begin{aligned} v & =\frac{k q}{r}=\frac{k ze}{r} \\ v & =\frac{9 \times 10^9 \times 80 \times 10^{-19}}{9 \times 10^{-15}} \end{aligned}
v=80\times 10^{5}=8\times 10^{6}\ volt

Posted by

Kuldeep Maurya

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