Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The experimental data for the reaction <img alt="2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})" src="/latex-image/?2%20%5Cmathrm%7BNO%7D%28%5Cmathrm%7

The experimental data for the reaction 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g}) are given below

Experiment [Cl2] [NO] Initial rate
1. 0.40 0.20 2.4 \times 10^{-4}
2. 0.40 0.60 2.16 \times 10^{-3}
3. 0.80 0.60 4.32 \times 10^{-3}

What is the order of the reaction ?

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

0


Answers (1)

2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})

\mathrm{r=k\left[\mathrm{C}_2\right)^x[\mathrm{NO})^y}

From equation (1) and (2) 

\mathrm{\frac{2.16 \times 10^{-3}}{2.4 \times 10^{-4}}=\frac{k(0.40)^x(0.60)^y}{k(0.40)^x(0.20)^y} \Rightarrow y=2}

                                                                                        \mathrm{x+y=3}

From eqaution (2) and (3)

\mathrm{\frac{2.16 \times 10^{-3}}{4.32 \times 10^{-3}}=\frac{k[0.40)^x[0.60]^y}{k[0.80)^x[0.60]^y} \Rightarrow x=1}

Posted by

Kshitij

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'PM Modi personally supervising the situation': Centre tells SC in NEET case
anam-khan

NEET Paper Leak Row: NTA informs SC of security overhaul, institutional reforms
anam-khan

Re-NEET 2026 City Intimation Slip LIVE: NTA MBBS admit card soon; direct link, login details, exam date

Latest Question