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The figure  shows an experimental plot for discharging of a capacitor in an R-C circuit. The time constant \tau of this circuit lies between :

Option: 1

150 sec and 200 sec


Option: 2

0 and 50 sec


Option: 3

50 sec and 100 sec


Option: 4

100 sec and 150 sec


Answers (1)

best_answer

 

R C Circuit Voltage -

V_{R}=IR

V_{C}={I}X_{C}

- wherein

 

 

During discharging of a capacitor

V= V_{0}e^{-t/\tau }

Where \tau  is the time constant of RC circuit

at T=\tau ,

V= \frac{V_{o}}{e}=0.37 V_{0}

From\: the \: graph,t=0,V_{0}=25V

\therefore V=0.37\times 25V= 9.25V

This voltage occurs at time lies between 100 sec and 150 sec . Hence, time constant \tau  of this circuit lies between

100 sec and 150 sec

 

 

Posted by

manish painkra

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