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  • The formation of <img alt="\mathrm{O}_{2}{ }^{+}\left[\mathrm{PtF}_{6}\right]^{-}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BO%7D_%7B2%7D%7B%20%7D%5E%7B&plus;%7D%5Cleft%5

The formation of \mathrm{O}_{2}{ }^{+}\left[\mathrm{PtF}_{6}\right]^{-}is the basis for the formation of xenon fluorides. This is because:

Option: 1

\mathrm{O}_{2} and \mathrm{Xe} have comparable sizes.


Option: 2

Both \mathrm{O}_{2} and \mathrm{Xe} are gases.


Option: 3

\mathrm{O}_{2} and \mathrm{Xe} have comparable ionisation energies.


Option: 4

\mathrm{O}_{2} and \mathrm{Xe} have comparable electronegativities.


Answers (1)

best_answer

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical.

Based on the above facts it is suggested that since oxygen combines with \mathrm{PtF}_{6}, so xenon should also form similar compound with \mathrm{PtF}_{6}.

Posted by

Ajit Kumar Dubey

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