Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The formation of <img alt="\mathrm{O}_{2}{ }^{+}\left[\mathrm{PtF}_{6}\right]^{-}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BO%7D_%7B2%7D%7B%20%7D%5E%7B&plus;%7D%5Cleft%5

The formation of \mathrm{O}_{2}{ }^{+}\left[\mathrm{PtF}_{6}\right]^{-}is the basis for the formation of xenon fluorides. This is because:

Option: 1

\mathrm{O}_{2} and \mathrm{Xe} have comparable sizes.


Option: 2

Both \mathrm{O}_{2} and \mathrm{Xe} are gases.


Option: 3

\mathrm{O}_{2} and \mathrm{Xe} have comparable ionisation energies.


Option: 4

\mathrm{O}_{2} and \mathrm{Xe} have comparable electronegativities.


Answers (1)

best_answer

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical.

Based on the above facts it is suggested that since oxygen combines with \mathrm{PtF}_{6}, so xenon should also form similar compound with \mathrm{PtF}_{6}.

Posted by

Ajit Kumar Dubey

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'PM Modi personally supervising the situation': Centre tells SC in NEET case
anam-khan

NEET Paper Leak Row: NTA informs SC of security overhaul, institutional reforms
anam-khan

Re-NEET 2026 City Intimation Slip LIVE: NTA MBBS admit card soon; direct link, login details, exam date

Latest Question