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  • The frequencies of alleles 'A' and 'a' in a population at Hardy-Weinberg equilibrium are 0.7 and 0.3 respectively. In a random sample of 250 individuals taken from the population, h

The frequencies of alleles 'A' and 'a' in a population at Hardy-Weinberg equilibrium are 0.7 and 0.3 respectively. In a random sample of 250 individuals taken from the population, how many are expected to be heterozygous?

 

Option: 1

112


Option: 2

81


Option: 3

105


Option: 4

 145


Answers (1)

best_answer

To determine the number of individuals expected to be heterozygous in a random sample of 250 individuals from a population at Hardy-Weinberg equilibrium, we need to use the Hardy-Weinberg equation. The equation for calculating the expected frequency of heterozygotes (pq) is:

2 X p X q X N

Where:
p = frequency of allele A

q = frequency of allele a

N = sample size (number of individuals)

Given that the frequencies of alleles A and a are 0.7 and 0.3 respectively, we can substitute these values into the equation:

2 X 0.7 X 0.3 X 250 = 105 individuals

Therefore, we can expect approximately 105 individuals in the random sample of 250 individuals to be heterozygous.

Hence, the correct answer is option 3.

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Riya

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