Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The gravitational field intensity due to a uniform solid sphere at a distance r (for outside the solid sphere)  from its center is proportional to: <div class='qna-opti

The gravitational field intensity due to a uniform solid sphere at a distance r (for outside the solid sphere)  from its center is proportional to: 

Option: 1

r^2


Option: 2

r


Option: 3

\frac{1}{r^2}


Option: 4

\frac{1}{r}


Answers (1)

best_answer

The gravitational field intensity due to a uniform solid sphere is proportional to \frac{1}{r^2}, where r is the distance from the center of the sphere, for points outside the solid sphere.

 

Posted by

Gunjita

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC NEET UG 2024 Counselling: Special round schedule out; choice filling begins from November 20
anam-khan

Rajasthan NEET UG counselling board cancels MBBS admissions of 100 students at PMCH
anam-khan

100 MBBS students’ fate uncertain as HC reverses ruling on extra seats at Rajasthan private medical college

Latest Question