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The half-life of a second-order reaction is dependent on concentration of Reactant:-
 

Option: 1

Directly proportional
 


Option: 2

Inversely proportional
 


Option: 3

Independent


 


Option: 4

None of these.


Answers (1)

best_answer

for a second order reaction
\mathrm{ t_{1 / 2}=\frac{1}{ \left [ A \right ]_0 K} \quad \Rightarrow \quad t_{1 / 2} \propto \frac{1}{\mid A]_0} }

Hence option 2 is correct.

Posted by

Kuldeep Maurya

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