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  • The half-life of radioactive Radon is 3.8 days. The time at the end of which (1/20)th of the Radon sample will remain undecayed is (given log10e = 0.4343)<str

The half-life of radioactive Radon is 3.8 days. The time at the end of which (1/20)th of the Radon sample will remain undecayed is (given log10e = 0.4343)

Option: 1

13.8 days


Option: 2

16.5 days


Option: 3

33 days


Option: 4

1.2 


Answers (1)

best_answer

\begin{aligned} & \left(\frac{1}{2}\right)^{\mathrm{n}}=\frac{\mathrm{N}}{\mathrm{N}_0}=\frac{1}{20} \text { gives } \mathrm{n}=4.32 \\ & \mathrm{t}=\mathrm{nT}=4.3 \times 3.8=16.5 \text { days } \end{aligned}

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Deependra Verma

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