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The heat of combustion of one gram mole of acetic acid in a bomb calorimeter was found to be -15 KJ at 25°C. Calculate the enthalpy of combustion (in KJ) of acetic acid at 25°C.

Option: 1

-15


Option: 2

15


Option: 3

-20


Option: 4

20


Answers (1)

best_answer

The combustion reaction of acetic acid,

\mathrm{CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)}

As the number of moles of gas before and after the reaction are the same hence \Deltan = 0;

The heat of combustion = Enthalpy of combustion 

Enthalpy of combustion = -15 kJ/mole

Posted by

avinash.dongre

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