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  • The impedance(Z) of given circuit is 2<img alt="k \Omega" src="http://

The impedance(Z) of given circuit is 2k \Omega, the inductance (in H) of circuit is

Option: 1

9.18


Option: 2

4.32


Option: 3

0.001


Option: 4

10.02


Answers (1)

best_answer

As we learnt

 

Impedence -

 

Z= \sqrt{R^{2}+4\pi ^{2}\nu ^{2}L^{2}}

-

 

 Z= \sqrt{R^{2}+X_L^{2}}

Z^{2}= R^{2}+X_L^{2}

X_L^{2}=Z^{2}- R^{2}

\left (\omega L \right )=\sqrt{Z^{2}- R^{2}}

2\pi f L=\sqrt{Z^{2}- R^{2}}

L=\frac{\sqrt{Z^{2}- R^{2}}}{2\pi f}

L=\frac{\sqrt{(4-1)*10^6}}{2*3.14*30}

L=9.18H

 

Posted by

Shailly goel

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