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  • The input resistance of a common emitter transistor amplifier, if the output resistance is <img alt="500\mathrm{K\Omega}" src="https://entrancecorner.oncodecogs.com/gif.latex?500%5Cmathrm%7BK%5COme

The input resistance of a common emitter transistor amplifier, if the output resistance is 500\mathrm{K\Omega}, the current gain \alpha =0.98 and power gain is 6.0625\times10^{6}, is
 

Option: 1

198\Omega


Option: 2

300\Omega


Option: 3

100\Omega


Option: 4

400\Omega


Answers (1)

best_answer

Voltage gain \mathrm{=A_v=\beta \frac{R_2}{R_1}}
Also, current gain \mathrm{\beta=\frac{\alpha}{1-\alpha}=\frac{0.98}{1-0.98}=49}

\mathrm{ A_V=(49)\left[\frac{500 \times 10^3}{R_1}\right] }

Power gain

\mathrm{ =6.0625 \times 10^6=49 \times\left[\frac{500 \times 10^3}{R_1}\right] \times 49 }

\mathrm{ \therefore R_1=198 \Omega }

Hence option 1 is correct.



 

Posted by

HARSH KANKARIA

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