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  • The ionisition potential of hydrogen atom, <img alt="\begin{aligned} & \mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, e=1.60 \times 10^{-19} \mathrm{c}, \\ &\mathrm{ m}=9.11 \t

The ionisition potential of hydrogen atom,

\begin{aligned} & \mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, e=1.60 \times 10^{-19} \mathrm{c}, \\ &\mathrm{ m}=9.11 \times 10^{-31} \mathrm{~kg} \text { and } \epsilon_0=8.85 \times 10^{-12} \mathrm{c}^2 / \mathrm{Nm}\\ \end{aligned}

 

Option: 1

13.6 \mathrm{ev}


Option: 2

15 \mathrm{ev}


Option: 3

14 \mathrm{eV}


Option: 4

16 \mathrm{eV}


Answers (2)

best_answer

\mathrm{Here, n=1 \quad \& \quad z=1}\\ \\ \begin{aligned} \mathrm{E_1=-\frac{m e^4}{8 \epsilon_0^2 \omega^2} }& =\mathrm{-\frac{9.11 \times 10^{-31} \times\left(1.60 \times 10^{-19} \mathrm{c}\right)^4}{8\left(0.85 \times 10^{-12}\right)\left(6.63 \times 10^{-34}\right)^2} }\\ &\mathrm{ =-2.17 \times 10^{-10} \mathrm{~J} }\\ & \mathrm{=-\frac{2.17 \times 10^{-18}}{1.6 \times 10^{-19}}=-13.6 \mathrm{eV} }\end{aligned}

The ionisation potential is 13.6 \mathrm{ev} 

Posted by

Ajit Kumar Dubey

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13.6eV

Posted by

Guru G

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