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The junction diode in the following circuit requires a minimum current of 1 \mathrm{~mA} to be above the knee point \mathrm{(0.7 \mathrm{~V})} of its \mathrm{I-V}characteristic curve. The voltage across the junction diode is independent of current above the knee point, if \mathrm{V_B=4 \mathrm{~V}}, then the maximum value of \mathrm{R} so that the voltage is above knee point will be


 

Option: 1

3.3 \mathrm{k} \Omega
 


Option: 2

4.0 \mathrm{k} \Omega
 


Option: 3

4.7 \mathrm{k} \Omega
 


Option: 4

6.6 \mathrm{k} \Omega


Answers (1)

best_answer

\mathrm{ V_B=V_{\text {knee }}+I R }

\mathrm{ \text { or } 4=0.7+10^{-3} R }

\mathrm{ \text { or } R=3.3 / 10^{-3}=3.3 \times 10^3 \Omega }

Hence option 1 is correct.


 

Posted by

Rakesh

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