Get Answers to all your Questions

header-bg qa

The largest wavelength in the ultraviolet region of the hydrogen spectrum is 122\ \mathrm{nm}. The smallest wavelength in the infrared region of the hydrogen spectrum is -

Option: 1

\mathrm{802\ nm}


Option: 2

\mathrm{823\ nm}


Option: 3

\mathrm{1882\ nm}


Option: 4

\mathrm{1648\ nm}


Answers (1)

best_answer

The series is \mathrm{U-V} region is Lyman series. longest wavelength corresponding to minimum energy which occurs in transition from \mathrm{n=2\ to\ n=1}
\mathrm{122=\frac{1 / R}{\left(\frac{1}{1^2}-\frac{1}{2^2}\right)}..........\left ( 1 \right )}
The smallest wave length in the infrared region corresponds to maximum energy of paschen series.
\mathrm{\lambda=\frac{1 / R}{\left(\frac{1}{3^2}-\frac{1}{\infty}\right)}...........\left ( 2 \right )}
Divide \mathrm{\left ( 1 \right )} and \mathrm{\left ( 2 \right )}
\mathrm{\frac{122}{\lambda}=\frac{1 / R}{\left(1-\frac{1}{4}\right)} \times \frac{\frac{1}{9}}{1 / R}=\frac{1}{9} \times \frac{4}{3}}
\mathrm{\lambda =823.5\ nm}

Posted by

SANGALDEEP SINGH

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks