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  • The magnetic flux linked with a coil (in Wb) is give by the  equation

The magnetic flux linked with a coil (in Wb) is give by the  equation

\phi =5t^{2}+3t +16

The magnitude of induced emf in the coil at the fourth second will be

 

Option: 1

43 V


Option: 2

108 V


Option: 3

10 V


Option: 4

33 V


Answers (1)

best_answer

The magnitude of induced emf is given by

\left | e \right |=\frac{d\phi }{dt}=\frac{d(5t^{2}+3t+16) }{dt}

\left | e \right |=10t+3+0

at t = 4 s

\left | e \right |=40+3=43

Posted by

Rakesh

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