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  • The mass of the three wires of copper are in the ratio 1: 3: 5. And their length are in ratio 5: 3: 1. The ratio of their electrical resistance isOption: 1</stro

The mass of the three wires of copper are in the ratio 1: 3: 5. And their length are in ratio 5: 3: 1. The ratio of their electrical resistance is

Option: 1

1 : 3 : 5 


Option: 2

5 : 3 : 1 


Option: 3

1 : 15 : 125 


Option: 4

125 : 15 : 1


Answers (1)

best_answer

\mathrm{ R=\frac{\rho l}{A}=\frac{\rho l^2}{A l}=\frac{\rho l^2}{V}=\frac{\rho l^2}{m / d}=\frac{\rho d l^2}{m} \text { or } R \propto \frac{l^2}{m} }
\mathrm{ R_1: R_2: R_3=\frac{l_1^2}{m_1}: \frac{l_1^2}{m_2}: \frac{l_3^2}{m_3}=\frac{25}{1}: \frac{9}{3}: \frac{1}{5}=125: 15: 1 }

Posted by

manish painkra

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