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  • The Maximum temperature for ultraviolet part of radiation of EM waves. Take frequency of ultraviolet part of radiation as <img alt="\mathrm{8 \times 10^{14} \mathrm{~Hz} \; to\; 5 \times 10^{1

The Maximum temperature for ultraviolet part of radiation of EM waves. Take frequency of ultraviolet part of radiation as \mathrm{8 \times 10^{14} \mathrm{~Hz} \; to\; 5 \times 10^{17} \mathrm{~Hz}.}

Option: 1

4.73 \times 10^3 \mathrm{~K}


Option: 2

2.83 \times 10^6 \mathrm{~K}


Option: 3

7.73 \times 10^3 \mathrm{~K}


Option: 4

4.83 \times 10^6 \mathrm{~K}


Answers (1)

best_answer

The corresponding wavelength to the frequency \mathrm{8 \times 10^{14} \mathrm{~Hz} \text { is } \lambda_1=\mathrm{c} / v_1}

                  \mathrm{=3.75 \times 10^{-7} \mathrm{~m}}

                  The corresponding wavelength to the frequency \mathrm{5 \times 10^{17} \mathrm{~Hz} \text { is } \lambda_2=c / v_2}

                   \mathrm{=6 \times 10^{-10} \mathrm{~m}}

                  \mathrm{\text { As } \lambda_m \times T=2.9 \times 10^{-3} \text { so } T_1=7.73 \times 10^3 \mathrm{~K} \text { and } T_2=4.83 \times 10^6 \mathrm{~K}}

                  Temperature ranges \mathrm{7.73 \times 10^3 \mathrm{~K} \text { to } 4.83 \times 10^6 \mathrm{~K}}

                  Maximum Temperature is \mathrm{4.83 \times 10^6 \mathrm{~K}}

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