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  • The moment of inertia of a uniform cylinder of length 6m and radius 2m about an axis perpendicular to its plane and passing through one of its end is given by - [given mass of cylinder is 1kg]

The moment of inertia of a uniform cylinder of length 6m and radius 2m about an axis perpendicular to its plane and passing through one of its end is given by - [given mass of cylinder is 1kg]

Option: 1

1kgm2


Option: 2

3kgm2


Option: 3

9kgm2


Option: 4

13kgm2


Answers (1)

best_answer

I_{c.m}=\frac{mr^{2}}{4}+\frac{ml^{2}}{12}\\I=I_{c.m}+m(\frac{l}{2})^{2}\\I=\frac{mr^{2}}{4}+\frac{ml^{2}}{12}+\frac{ml^{2}}{4}\\ I=\frac{1\times4}{4}+\frac{1\times6^{2}}{12}+\frac{1\times6^{2}}{4}=13kgm^{2}

Posted by

shivangi.shekhar

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