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  • The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of <img alt="3.3 \times 10^{-3}watt" src="/latex-im

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 \times 10^{-3}watt will be :\left ( h=6.6\times 10^{-34}Js \right )

Option: 1

10^{18}
 


Option: 2

10^{17}


Option: 3

10^{16}

 


Option: 4

10^{15}


Answers (1)

best_answer

\lambda =600nm

P=3.3\times 10^{-3}w

h=6.6\times 10^{-34}Js

No. of  photons per second=\frac{p}{\frac{hc}{\lambda }}=\frac{3.3\times 10^{-3}}{\frac{6.6\times 10^{-34}\times 3\times 10^{8}}{6\times 10^{-7}}}

                                        =1\times 10^{16}

Posted by

rishi.raj

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