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The pairs of species of oxygen and their magnetic behaviours are noted below.
Which of the following presents the correct description?

Option: 1

O+2, O2 - Both paramagnetic


Option: 2

  O+2, O22- - Both paramagnetic


Option: 3

\text{O}_{2}^{-},\text{O}_{2}^{-2} - Both diamagnetic


Option: 4

\text{O}^{+},\text{O}_{2}^{2-} - Both paramagnetic


Answers (1)

best_answer

Electronic configuration of O_{2} molecule 

\sigma_{2s}^{2}\;\sigma_{2s}^{*2} \; \sigma_{2p}^{2}\; \pi_{2px}^{2}\; \pi_{2py}^{2}\; \pi_{2px}^{*1}\; \pi_{2py}^{*1}

Since there are 2 unpaired electrons in 2p_x & 2p_y degenerate orbitals, so, O_{2} is paramagnetic.

 

Similarly for O_{2}^{+} molecule, we have 

\sigma_{2s}^{2}\;\sigma_{2s}^{*} \; \sigma_{2p}^{2}\; \pi_{2p}^{2}\; \pi_{2py}^{2}\; \pi_{2px}^{*1}

Since, there is 1 unpaired electron in 2p_x orbital, 

\therefore O_{2}^{+} is paramagnetic.

As O_{2}^{+},O_{2},O_{2}^{-},O and O^{+} have unpaired electrons, hence are paramagnetic. The species which have unpaired electrons has paramagnetic behaviour.

Posted by

chirag

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