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The radii of two concentric circular coils are 8 cm and 10 cm and the number of turn in them is 40 and 10 respectively. A current is passing through each of them in same direction. Determine the magnetic field produced at the center of the two coils is 

Option: 1

1.88\times10^{-3}


Option: 2

1.88\times10^{-2}


Option: 3

1.98\times10^{-3}


Option: 4

None


Answers (1)

best_answer

As current flows in the same direction through the two coils, the
direction of magnetic field at the center due to the coils will be
same. Hence, the resultant magnetic field will be

For the first coil, B_1= \frac{\mu_0N_1I}{2A_1}

For the second coil, B_2= \frac{\mu_0N_2I}{2A_2}

\thereforeThe resultant magnetic field, 

B = B_1+B_2

=\frac{\mu_0I}{2}\left( \frac{N_1}{A_1}+\frac{N_2}{A_2}\right)=\frac{4\pi\times10^{-7}\times5}{2}\left( \frac{40}{8}+\frac{10}{10}\right)

=1.88\times10^{-3}wb/m^{2}

Posted by

Anam Khan

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