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  • The rate of certain biochemical reaction at physiological temperature (T) occurs times f

The rate of certain biochemical reaction at physiological temperature (T) occurs \mathrm{10^8} times faster with enzyme than without. The change in the activation energy upon adding enzyme is

Option: 1

\mathrm{-10RT}


Option: 2

\mathrm{+8RT}


Option: 3

\mathrm{-8(2.303) R T}


Option: 4

\mathrm{-12(6.202) R T}


Answers (1)

best_answer

The rate constant of a reaction is giver by

\mathrm{ K=A e^{-E a / R T} }

The rate constant in presence of catalyst is
\mathrm{ \begin{aligned} & K^{\prime}=A e^{-E a^{\prime} / R T} \\\\ & \frac{K^{\prime}}{K}=e^{-\left(E a^{\prime}-E a\right) / R T} \\\\ & 10^8=e^{-\left(E a^{\prime}-E a\right) / R T} \\\\ & \ln 10^8=-\frac{\left(E a^{\prime}-E a\right)}{R T} \\\\ & E a^{\prime}-E a=-8(2.303) R T \end{aligned} }

Posted by

Pankaj Sanodiya

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