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  • The rate of reaction doubles when its temperature changes from

The rate of reaction doubles when its temperature changes from \mathrm{250 \mathrm{~K}} to 270 \mathrm{~K}. Calculate the activation energy of the reaction will be

Option: 1

2033


Option: 2

2148


Option: 3

1697


Option: 4

19451


Answers (1)

best_answer

\mathrm{\begin{aligned} \frac{\log k_2}{\log k_1} & =\frac{E a}{2.303 R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right) \\\\ \frac{k_2}{k_1} & =2 ; \, \, \, \, T_2=270 K ; \, \, \, T_1=250 K \\\\ \log 2 & =\frac{E a}{2.303 \times 8.314}\left(\frac{1}{250}-\frac{1}{270}\right) \\\\ E a & =19451 \end{aligned}}

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Divya Prakash Singh

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