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  • The ratio of maximun to minimum wavelength in Balmer series is  Option: 1 3:4 Option:

The ratio of maximun to minimum wavelength in Balmer series is
 

Option: 1

3:4 


Option: 2

1:4 


Option: 3

5:36 


Option: 4

5:9


Answers (1)

For Balmer series n=2

\begin{aligned} & \frac{1}{\lambda_{\max }}=\mathrm{R} Z^2\left(\frac{1}{2^2}-\frac{1}{\infty^2}\right) \text { and } \frac{1}{\lambda_{\min }}=R Z^2\left(\frac{1}{2^2}-\frac{1}{3^2}\right) \\ & \frac{1 / \lambda_{\min }}{1 / \lambda_{\operatorname{mix}}}=\frac{\left(1 / 2^2-1 / 3^2\right)}{\left(1 / 2^2\right)}=\frac{\frac{1}{4}-\frac{1}{9}}{1 / 4}=1-\frac{4}{9}=5 / 9 \\ & \frac{\lambda_{\text {mix }}}{\lambda_{\min }}=\frac{5}{9} \end{aligned}

Posted by

Sumit Saini

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