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  • The RMS value of the electric field of the light coming from the sun is 720 N/C. The average total energy density of the electromagnetic wave isOption: 1</strong

The RMS value of the electric field of the light coming from the sun is 720 N/C. The average total energy density of the electromagnetic wave is

Option: 1

3.3 \times 10^{-3} \mathrm{~J} / \mathrm{m}^3\\


Option: 2

4.58 \times 10^{-6} \mathrm{~J} / \mathrm{m}^3\\


Option: 3

6.37 \times 10^{-9} \mathrm{~J} / \mathrm{m}^3\\


Option: 4

81.35 \times 10^{-12} \mathrm{~J} / \mathrm{m}^3


Answers (1)

best_answer

\begin{aligned} & \mathrm{U}=(1 / 2) \epsilon_0\left(\mathrm{E}_{\mathrm{rms}}^2\right)+\left(1 / 2 \mu_0\right)\left(\mathrm{B}_{\mathrm{rms}}^2\right) \\ \\& \mathrm{U}=(1 / 2) \epsilon_0\left(\mathrm{E}_{\mathrm{rms}}^2\right)+\left(1 / 2 \mu_0\right)\left(\mathrm{E}_{\mathrm{rms}}^2 / \mathrm{c}^2\right) \\ \\& \mathrm{U}=(1 / 2) \epsilon_0\left(\mathrm{E}_{\mathrm{rms}}^2\right)+\left(1 / 2 \mu_0\right)\left(\mathrm{E}_{\mathrm{rms}}^2 \epsilon_0 \mu_0\right) \\ \\& \mathrm{U}=(1 / 2) \epsilon_0\left(\mathrm{E}_{2 \mathrm{mms}}\right)+(1 / 2) \epsilon_0\left(\mathrm{E}_{2 \mathrm{rms}}\right)=\epsilon_0\left(\mathrm{E}_{2 \mathrm{rms}}\right) \\ \\& \mathrm{U}=\left(8.85 \times 10^{-12}\right) \times(720)^2=4.58 \times 10^{-6} \mathrm{Jm}^{-1} \end{aligned}

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