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The second order diffraction pattern of \mathrm{x}- ray with \mathrm{\lambda=1 A^{\circ}} from a set of parallel plane in a metal occur at an angle of \mathrm{60^{\circ}}. The distance between scattering planes in crystal is -

Option: 1

\mathrm{{2 \sqrt{3} \AA}}


Option: 2

\mathrm{\frac{\sqrt{3}}{2} \AA}


Option: 3

\mathrm{\frac{2 \sqrt{3}}{3} \AA}


Option: 4

\mathrm{\frac{3 \sqrt{3}}{2} \AA}


Answers (1)

best_answer

According to Bragg's law - 
Here, \mathrm{n=2}               \mathrm{n\lambda =2d\ sin \Theta }
        \mathrm{\lambda =1\AA }              \mathrm{2\lambda =2d\ sin\ 60^{\circ}}
        \mathrm{\Theta =60^{\circ} }               \mathrm{\lambda =d\ sin\ 60^{\circ}} 
                                                          

      \mathrm{\Rightarrow d=\frac{\lambda }{sin\ 60^{\circ}}}
                                                         

       \mathrm{d=\frac{1 A}{\sqrt{3} / 2}=\frac{2 \sqrt{3}}{3} \AA}

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SANGALDEEP SINGH

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