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  • The second order diffraction pattern of x-ray with  from a set of parall

The second order diffraction pattern of x-ray with \lambda=1 \dot{A} from a set of parallel plane is a metal occur at an angle of 60^{\circ}. The distance between scattering planes in crystal is-

Option: 1

\mathrm{2 \sqrt{3} \AA}


Option: 2

\mathrm{\frac{\sqrt{3}}{2} \AA}


Option: 3

\mathrm{\frac{2 \sqrt{3}}{3} \AA}


Option: 4

\mathrm{\frac{3 \sqrt{3}}{2} \AA}


Answers (1)

According to Bragg's law-

Here,

 \begin{aligned} &\begin{aligned} & n=2 \\ & \lambda=1 \AA \\ & \theta=60^{\circ} \end{aligned}\\ &n \lambda=2 d \sin \theta\\ &2 \lambda=2 d \sin 60^{\circ}\\ &\begin{aligned} \lambda=d \sin 60^{\circ} \Rightarrow d & =\frac{\lambda}{\sin 60^{\circ}} \\ d & =\frac{1 A}{\sqrt{3} / 2}=\frac{2 \sqrt{3}}{3} A \end{aligned} \end{aligned}

Posted by

Ramraj Saini

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