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  • The specific rate constant of decomposition of a compound is represented by <img alt="\mathrm{\ln \mathrm{k}=15.0-15000 / \mathrm{T}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm

The specific rate constant of decomposition of a compound is represented by \mathrm{\ln \mathrm{k}=15.0-15000 / \mathrm{T}}. The activation energy of energy of decomposition for this compound at \mathrm{300 \mathrm{~K}} is:
 

Option: 1

29.7 \mathrm{kcal} / \mathrm{mole}


Option: 2

12 \mathrm{kcal} / \mathrm{mole}


Option: 3

24 \mathrm{cal} / \mathrm{mole}


Option: 4

12 \mathrm{cal} / \mathrm{mole}


Answers (1)

best_answer

\begin{aligned} \ln \text{k} & =15-\frac{15000}{T} \\ \\\text{k} & = \mathrm{A e^{-E_a / R T}} \\ \\\ln \text{k} & = \mathrm{\ln A-E_a / R T} \\ \\\mathrm{\frac{E_9}{R T}} & =\mathrm{ \frac{15000}{T} }\\ \\\mathrm{E_a} & =15000 \times 1.987 \\ \\\mathrm{E_a} & =29.7\: \mathrm{kcal} / \mathrm{mol} \end{aligned}

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manish painkra

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