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  • The thermel decomposition of compound follows the second order kinetics if the rate of reaction is <img alt="0.3\; \mathrm{mol}\; \mathrm{L}^{-1} \mathrm{~S}^{-1}" src="https://entrancecorner.oncod

The thermel decomposition of compound follows the second order kinetics if the rate of reaction is 0.3\; \mathrm{mol}\; \mathrm{L}^{-1} \mathrm{~S}^{-1} when the concentration of reactant is 0.2 \mathrm{~mol}^{-1} then what will be the rate reaction the concentration is increased three time of its initial concentration

Option: 1

0.30 \; \mathrm{mol\; L}^{-1} \mathrm{~s}^{-1}


Option: 2

0.9 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}


Option: 3

0.60 \mathrm{~mol\; L} ^{-1} \mathrm{~s}^{-1}


Option: 4

2.7 \: \mathrm{mol\: L}^{-1} \mathrm{~s}^{-1}


Answers (1)

best_answer

\begin{aligned} r & =k(A)^2 \\ \\0.3 & =k(0.2)^2 \\ \\k & =\frac{0.3}{(0.2)^2} \end{aligned}

\mathrm{Now (A)^{\prime} \rightarrow 3(A)}

\begin{gathered} \\r_2=k\left([A)^{.}\right)^2=\frac{0.3}{(0.2)^2} \times(3 \times 0.2)^2 \\ \\r_2=9 \times 0.3=2.7 \\ \\r_2=2.7 \mathrm{moll} L^{-1} \mathrm{~s}^{-1} \end{gathered}

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Ritika Jonwal

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