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The thermo e.m.f. E in volts of a certain thermo-couple is found to vary with temperature difference \theta in °C between the two junctions according to the relation

\text{E}=300-\frac{\theta_{2}}{15}.

The neutral temperature for the thermo-couple will be

Option: 1

450°C


Option: 2

400°C


Option: 3

225°C


Option: 4

30°C


Answers (1)

best_answer

\\ E=30 \theta-\frac{\theta^{2}}{15}$ \\ At neutral temperature $\frac{d E}{d \theta}=0$ \\ therefore, $30-\frac{2 \theta}{15}=0$ \\ Or, $\theta=225^{\circ} \mathrm{C}$

Posted by

Sanket Gandhi

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