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  • The threshold frequency for a metallic surface corresponds to an energy of , and the stopping potential fo

The threshold frequency for a metallic surface corresponds to an energy of 6.2 \ eV, and the stopping potential for a radiation incident on this surface is 5V. The incident radiation lies in -

Option: 1

X-ray region


Option: 2

ultraviolet region


Option: 3

infrared region


Option: 4

visible region


Answers (1)

best_answer

\begin{aligned} & \mathrm{E}=\phi+e \mathrm{V}_0 \\ & \mathrm{E}=6.2 \mathrm{eV}+5 \mathrm{eV}=11.2 \mathrm{eV} \\ & \lambda=\frac{12420}{11.2}=1108.9 \mathrm{eV} \end{aligned}
Which lies in U.V. region.

Posted by

Gautam harsolia

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