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  • The van't Hoff factor i for a compound which undergoes dissociation in one solvent and association in other solvent is respectively :Option: 1 Gr

The van't Hoff factor i for a compound which undergoes dissociation in one solvent and association in other solvent is respectively :

Option: 1

Greater than one and greater than one


Option: 2

Less than one and greater than one


Option: 3

Less than one and less than one


Option: 4

Greater than one and less than one


Answers (1)

best_answer

Van't Hoff factor for the association, 

i=1-\alpha +\frac{\alpha }{n} ,

Where n=2 for dimerization and n=3 for trimerization

i=1-\alpha \left ( 1-\frac{1}{n} \right )

So, for the association "i" will be less than 1.

Now, 

Van't Hoff factor for dissociation,

 i=1+(n-1)\alpha , 

where n =2, 3 ....... (no. of dissociated particles)

So, for the dissociation "i" will be more than 1.

Therefore,

i > 1  for dissociation and i < 1 for association.

So, Option 4 is correct.

Posted by

Sayak

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