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The wires which connect the battery of an auto mobile to its starting motor carry a current of 30A (for a short five). What is the force per unit length between the wires, if they are 40cm long and 5cm apart

Option: 1

3.6 N/m


Option: 2

0.36 N/m


Option: 3

36 N/m


Option: 4

360 N/m


Answers (1)

best_answer

Field of one wire exerts force on other wive and the force per wire length of wire is \frac{F}{l}=\frac{\mu_0 2 I_1 I_2}{4 \pi d}.

so \frac{d F}{M}=\frac{\mu_0}{4 \pi}\left(\frac{2 F_1 F_2}{d}\right)

I_1=\Sigma_2=300 \mathrm{~A}, \gamma=5 \mathrm{~cm},=5 \times 10^{-2} \mathrm{~m}
so     \begin{aligned} \frac{d F}{d t} & =\frac{10^{-7} \times 2 \times 300 \times 300}{5 \times 10^{-2}} \\ \end{aligned}

                 \begin{aligned} & =3.6 \times 10^{-1} \mathrm{~N} / \mathrm{m}=0.36 \mathrm{~N} / \mathrm{m} \end{aligned}

Posted by

Gaurav

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