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  • Three similar light bulbs are connected to a constant voltage d.c. supply as shown in Figure. Each bulb operates at normal brightness and the ammeter (of negligible resistance) registers a steady c

Three similar light bulbs are connected to a constant voltage d.c. supply as shown in Figure. Each bulb operates at normal brightness and the ammeter (of negligible resistance) registers a steady current

The filament of one of the bulbs breaks. What happens to the ammeter reading and to the brightness of the remaining bulbs?

Option: 1

Ammeter reading - increases, Bulb brightness - increases

 


Option: 2

Ammeter reading - increases, Bulb brightness - unchanged

 


Option: 3

Ammeter reading - unchanged , Bulb brightness - unchanged

 

 


Option: 4

Ammeter reading - decreases, Bulb brightness - unchanged


Answers (1)

best_answer

Suppose V is the voltage of the supply and R is the resistance of each bulb
Now, \mathrm{R_P=\frac{R }{3}}  and current in ammeter, \mathrm{I=\frac{V }{R_P}=\frac{3 V}{R}},
Provided all three bulbs are working properly
If one bulb has broken down, then

\mathrm{R_P=\frac{R}{2} ~and ~I=2 \frac{V}{R} }

Therefore, current decreases and since current through each bulb is \mathrm{ \frac{V}{R} } the same as before, brightness of bulbs is not affected

Posted by

Sanket Gandhi

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