Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • To generate a power of , the number of fissions of  <img alt

To generate a power of 3.2\, \, \mathrm{MW}, the number of fissions of  U^{235} per minute is (Energy released per fission =200 \, \mathrm{MeV}, 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J} )

Option: 1

6 \times 10^{18}


Option: 2

6 \times 10^{17}


Option: 3

10^{17}


Option: 4

6 \times 10^{16}


Answers (1)

best_answer

Power of reactor  P=\frac{n E}{t}

Where 'n' is number of fissions 't' is time 'E' is energy released per fission

\therefore 3.2 \times 10^6=\frac{\mathrm{n}\left(200 \times 10^6\right)\left(1.6 \times 10^{-19}\right)}{60}

\Rightarrow \mathrm{n}=6 \times 10^{18}

Posted by

rishi.raj

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Punjab NEET PG 2025 round 3 counselling begins tomorrow for 280 seats; merit list on January 7
anam-khan

Uttarakhand NEET PG 2025 round 3 counselling registration begins; merit list on January 6
anam-khan

Tamil Nadu opens BDS special stray round 2 with NEET cut-off as low as 113, sets Rs 2 lakh security deposit

Latest Question