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To generate a power of 3.2\, \, \mathrm{MW}, the number of fissions of  U^{235} per minute is (Energy released per fission =200 \, \mathrm{MeV}, 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J} )

Option: 1

6 \times 10^{18}


Option: 2

6 \times 10^{17}


Option: 3

10^{17}


Option: 4

6 \times 10^{16}


Answers (1)

best_answer

Power of reactor  P=\frac{n E}{t}

Where 'n' is number of fissions 't' is time 'E' is energy released per fission

\therefore 3.2 \times 10^6=\frac{\mathrm{n}\left(200 \times 10^6\right)\left(1.6 \times 10^{-19}\right)}{60}

\Rightarrow \mathrm{n}=6 \times 10^{18}

Posted by

rishi.raj

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