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  • Two batteries with e:m.f 100 V and 120 V are connected in parallel across a load resistor of 50Ω. The internal resistances of the two batteri

Two batteries with e:m.f 100 V and 120 V are connected in parallel across a load resistor of 50Ω. The internal resistances of the two batteries are 6Ω and 12Ω respectively. The voltage across the load lies between-

Option: 1

106.7 \mathrm{~V} \& 106.8 \mathrm{~V}


Option: 2

106.6 \mathrm{~V} \&106.7 \mathrm{~V}


Option: 3

106.5 \mathrm{~V} \& 106.6 \mathrm{~V}


Option: 4

106.4 \mathrm{~V} \& 106.3 \mathrm{~V}


Answers (1)

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\begin{aligned} \text { Eeq } & =\frac{\sum E_{1} / R_{1}}{\sum R_{1}} \\ & =\frac{\frac{100}{6}+\frac{120}{12}}{1 / 6+1 / 12}=\frac{\frac{200}{12}+\frac{120}{12}}{\frac{2}{12}+\frac{1}{12}} \\ & =\frac{(200+120)}{12} \times \frac{12}{3} \\ & =\frac{320}{3}=106.67 \mathrm{~V} \end{aligned}

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seema garhwal

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