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Two circular current carrying coils of radii 3 \mathrm{~cm} and 6\mathrm{~cm} are each equivalent to a magnetic dipole having equal magnetic moments. The currents through the coils are in the ratio of

Option: 1

\sqrt{2}: 1


Option: 2

2: 1


Option: 3

2 \sqrt{2}: 1


Option: 4

4: 1


Answers (1)

best_answer

Magnetic moment

m_2 I A=I \pi r^2 \\

So, I_1 \pi r_1^2=I_2 \pi r_2^2 \\

 

\Rightarrow I_1 \pi(3)^2=I_2 \cdot \pi \cdot(6)^2 \\

\Rightarrow \frac{I_1}{I_2}=\left(\frac{6}{3}\right)^2=4: 1

 

 

Posted by

Sanket Gandhi

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