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Two circular rings of identical radii and resistance of \mathrm{36 \Omega}  each are placed in such a way that they cross each other"s center \mathrm{C_1} and \mathrm{C_2}  as shown in Figure. conducting joints are made at intersection points A and B of the rings. An ideal cell of e.m.f. 20 V is connected across A B. The power delivered by cell is

Option: 1

80 W


Option: 2

100 W


Option: 3

120 W


Option: 4

200 W


Answers (1)

best_answer

\mathrm{ A C_1=A C_2=C_1 C_2=\text { radius } }
\mathrm{ \angle A C_1 B=120^{\circ}}

The resistances of the four sections are \mathrm{ 24,12,12 ~and ~24 \Omega}  Hence, equivalent resistance R across AB is
\mathrm{ \frac{1}{R}=\frac{1}{24}+\frac{1}{12}+\frac{1}{12}+\frac{1}{24} \text { or } R=4 \Omega }
Therefore, power    \mathrm{ =\frac{v^3}{R}=\frac{(20)^2}{4}=100 \mathrm{~W} }

Posted by

Irshad Anwar

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