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  • Two coils of self inductance <img alt="\mathrm{L}_1 \text { and } \mathrm{L}_2" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BL%7D_1%20%5Ctext%20%7B%20and%20%7D%20%5Cmathrm%

Two coils of self inductance \mathrm{L}_1 \text { and } \mathrm{L}_2 are in parallels as shown in fig. If their Mutual inductance is M, then the effective inductance will be given by

 

 

 

 

Option: 1

\mathrm{\frac{L_1 L_2 M}{L_1+L_2+2 M}}


Option: 2

\mathrm{\frac{L_1 L_2 M^2}{L_1+L_2-2 M}}


Option: 3

\mathrm{\frac{L_1 L_2-M}{L_1+L_2+2 M}}


Option: 4

\mathrm{\frac{L_1 L_2-M^2}{L_1+L_2+2 M}}


Answers (1)

best_answer

When two inductances are in parallels then

\mathrm{L=\frac{L_1 L_2-M^2}{L_1+L_2+2 M}}

Posted by

Kuldeep Maurya

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