Get Answers to all your Questions

header-bg qa

FB155987-976D-42F7-97F1-C3D4E92A61A6.jpeg Two discs having masses in the ratio 1:2 and radii in the ratio 1:8 roll down without slipping one by one from an inclined plane of height h. The ratio of their linear velocities on reaching the ground is?

Answers (2)

@Fatema patel

here the potential energy is converted to kinetic energy

for disc 1 

m_1gh=\frac{1}{2}m_1v_1^2+\frac{1}{2}I\omega^2\\ since\ \omega=\frac{v}{r_1}and \ I=\frac{m_1r_1^2}{2}\\m_1gh=\frac{1}{2}m_1v_1^2+\frac{1}{2}\frac{m_1v_1^2}{2}=\frac{3m_1v_1^2}{4}\\so\ v_1=\sqrt{\frac{4gh}{3}}\\ simillarly\ v_2=\sqrt{\frac{4gh}{3}}\\therefor\ \frac{v_1}{v_2}=\frac{1}{1}

Posted by

Safeer PP

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks


Tell me this book name

Posted by

Darshan

View full answer